Be nha toi biet boc thtrc an Mng tay, nhung rat hay nghich thtrc
an.
An b�ng tay th� hi�n y muon ti)' an cua be. a m9t mtrc d9 nao do,
hay d� cho be dm;rc ti)' do. Nhung kh6ng nen d� be nghich thtrc an.
Tre doi se dung tay boc thtrc an ciing se cho thtrc an vao mi�ng. The nhung
neu an dtrQ'C !ting ht.mg, tre se dung thtrc an d� nghich chtr khf>ng cho vao
mi�ng. Neu the, bi,m hay hOi be "con co an nfra khong", "con no roi phai
kh6ng" roi dQn ban an.
Noi ro rang v&i tre la rat quan tr9ng. Di nhien kh6ng phai Ctr hoi la be tra
101
nhung Ctr J?p di J?p !;;ti vi�c nay, be Se hi�u khi bi m� hOi thi khay an se
dtrQ'C dQn di va bfra an se ket thuc. Co th� be con an dtrQ'C nfra nhung v�n
phai ctrong quyet. Hay lam cho be hi�u quy tac trong an uong.
kh6ng?
LtrQ'llg an cua be khong fin dinh, khi
be kh6ng thich thi dling bfra an cho
du ltrQ'llg an chtra du CO dtrQ'C
Khi be khong thich thi dling ep be. Khi
vi�c nay xay ra lien tl)C thi hay doi chieu v&i dm'mg Cong dQ trmmg
thanh cua be d� xac nMn.
Khi rang c&a cua be mQC, toi cho be an do an cting m9t chut co
dtrQ'C khf>ng?
Rang cua dung d� can. Doi v&i nhfrng do an ma be co th� can dtrQ'C
nhung vfo can
XU ly nhai va nghien nat cua rang ham thi hay dQ'i be
l&n hon m9t chllt.
Khi toi cho be an do da dtrQ'C chulln bi
(y
tr;;tng thai mem, min,
mQi vi�c tien tri�n tot nhung be rat m�n cam v&i nhfrng do h;;it
h;;it, l;;io x;;io. Chi can cam thily co m9t chut xiu thoi be ciing khong
an. Xin hay cho toi
101 khuyen?
Ciing co th� h;;it hoi to nhi. Hay th& che bien sao cho be khong co
cam giac l;;io x;;io m9t chllt.
